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####
##
## Get two rankings and compute the size of the k-intersection,
## i.e. the number of elements which are present in the first k
## positions of both rankings, as a function of k
##
##
import sys
if len(sys.argv)< 4:
print "Usage: %s <file1> <file2> <increment>" % sys.argv[0]
sys.exit(1)
incr = int(sys.argv[3])
rank1 = []
rank2 = []
lines = open(sys.argv[1], "r").readlines()
for l in lines:
n= l.strip(" \n").split(" ")[0]
rank1.append(n)
lines = open(sys.argv[2], "r").readlines()
for l in lines:
n= l.strip(" \n").split(" ")[0]
rank2.append(n)
N = len(rank1)
i = incr
while i < N+incr:
l = len(set(rank1[:i]) & set(rank2[:i]))
print i, l
i += incr
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